Base | Representation |
---|---|
bin | 1001100001011111… |
… | …11010011111111011 |
3 | 111012022200212202211 |
4 | 10300233322133323 |
5 | 40432341142133 |
6 | 2203201435551 |
7 | 240462241462 |
oct | 46057723773 |
9 | 14168625684 |
10 | 5112834043 |
11 | 2194074989 |
12 | ba833bbb7 |
13 | 636346bb5 |
14 | 3670739d9 |
15 | 1edce3bcd |
hex | 130bfa7fb |
5112834043 has 2 divisors, whose sum is σ = 5112834044. Its totient is φ = 5112834042.
The previous prime is 5112833993. The next prime is 5112834121. The reversal of 5112834043 is 3404382115.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5112834043 is a prime.
It is a super-2 number, since 2×51128340432 = 52282143902519451698, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5112833996 and 5112834014.
It is not a weakly prime, because it can be changed into another prime (5112835043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556417021 + 2556417022.
It is an arithmetic number, because the mean of its divisors is an integer number (2556417022).
Almost surely, 25112834043 is an apocalyptic number.
5112834043 is a deficient number, since it is larger than the sum of its proper divisors (1).
5112834043 is an equidigital number, since it uses as much as digits as its factorization.
5112834043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11520, while the sum is 31.
The square root of 5112834043 is about 71504.0841001407. The cubic root of 5112834043 is about 1722.7432835581.
The spelling of 5112834043 in words is "five billion, one hundred twelve million, eight hundred thirty-four thousand, forty-three".
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