Base | Representation |
---|---|
bin | 1001100001100001… |
… | …01000111011101010 |
3 | 111012100001112122221 |
4 | 10300300220323222 |
5 | 40432413233414 |
6 | 2203205504254 |
7 | 240463663123 |
oct | 46060507352 |
9 | 14170045587 |
10 | 5113024234 |
11 | 219419486a |
12 | ba841208a |
13 | 6363b2636 |
14 | 3670c304a |
15 | 1edd30224 |
hex | 130c28eea |
5113024234 has 4 divisors (see below), whose sum is σ = 7669536354. Its totient is φ = 2556512116.
The previous prime is 5113024207. The next prime is 5113024243. The reversal of 5113024234 is 4324203115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 4070057209 + 1042967025 = 63797^2 + 32295^2 .
It is a super-2 number, since 2×51130242342 = 52286033634942573512, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113024199 and 5113024208.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1278256057 + ... + 1278256060.
Almost surely, 25113024234 is an apocalyptic number.
5113024234 is a deficient number, since it is larger than the sum of its proper divisors (2556512120).
5113024234 is a wasteful number, since it uses less digits than its factorization.
5113024234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2556512119.
The product of its (nonzero) digits is 2880, while the sum is 25.
The square root of 5113024234 is about 71505.4140188000. The cubic root of 5113024234 is about 1722.7646445882.
Adding to 5113024234 its reverse (4324203115), we get a palindrome (9437227349).
The spelling of 5113024234 in words is "five billion, one hundred thirteen million, twenty-four thousand, two hundred thirty-four".
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