Base | Representation |
---|---|
bin | 100101001100111110100… |
… | …0111001010101101011011 |
3 | 200002210211102202012220220 |
4 | 1022121331013022231123 |
5 | 1132233122142104430 |
6 | 14512532542451123 |
7 | 1035260430600564 |
oct | 112317507125533 |
9 | 20083742665826 |
10 | 5113110113115 |
11 | 16a15043a6694 |
12 | 6a6b56293aa3 |
13 | 2b1219a1a394 |
14 | 139693a3716b |
15 | 8d00c8ae110 |
hex | 4a67d1cab5b |
5113110113115 has 32 divisors (see below), whose sum is σ = 8612618699520. Its totient is φ = 2583146715264.
The previous prime is 5113110113113. The next prime is 5113110113143.
5113110113115 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 5113110113115 - 21 = 5113110113113 is a prime.
It is a super-2 number, since 2×51131101131152 (a number of 26 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (5113110113113) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1208212 + ... + 3418478.
It is an arithmetic number, because the mean of its divisors is an integer number (269144334360).
Almost surely, 25113110113115 is an apocalyptic number.
5113110113115 is a deficient number, since it is larger than the sum of its proper divisors (3499508586405).
5113110113115 is a wasteful number, since it uses less digits than its factorization.
5113110113115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2218411.
The product of its (nonzero) digits is 225, while the sum is 24.
It can be divided in two parts, 5113110 and 113115, that added together give a palindrome (5226225).
The spelling of 5113110113115 in words is "five trillion, one hundred thirteen billion, one hundred ten million, one hundred thirteen thousand, one hundred fifteen".
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