Base | Representation |
---|---|
bin | 1110111000011001010… |
… | …00110011011110001001 |
3 | 1210212210021212100000020 |
4 | 13130030220303132021 |
5 | 31334132130201101 |
6 | 1030521034531053 |
7 | 51640546622622 |
oct | 7341450633611 |
9 | 1725707770006 |
10 | 511313131401 |
11 | 187934a29576 |
12 | 83119896a89 |
13 | 392a7bc0177 |
14 | 1aa67924a49 |
15 | d478e27136 |
hex | 770ca33789 |
511313131401 has 16 divisors (see below), whose sum is σ = 690652047360. Its totient is φ = 336428211600.
The previous prime is 511313131397. The next prime is 511313131429. The reversal of 511313131401 is 104131313115.
It is not a de Polignac number, because 511313131401 - 22 = 511313131397 is a prime.
It is a super-2 number, since 2×5113131314012 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (511313131501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 181726 + ... + 1027448.
It is an arithmetic number, because the mean of its divisors is an integer number (43165752960).
Almost surely, 2511313131401 is an apocalyptic number.
It is an amenable number.
511313131401 is a deficient number, since it is larger than the sum of its proper divisors (179338915959).
511313131401 is a wasteful number, since it uses less digits than its factorization.
511313131401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 848356.
The product of its (nonzero) digits is 540, while the sum is 24.
Adding to 511313131401 its reverse (104131313115), we get a palindrome (615444444516).
The spelling of 511313131401 in words is "five hundred eleven billion, three hundred thirteen million, one hundred thirty-one thousand, four hundred one".
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