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511313131397 is a prime number
BaseRepresentation
bin1110111000011001010…
…00110011011110000101
31210212210021212100000002
413130030220303132011
531334132130201042
61030521034531045
751640546622615
oct7341450633605
91725707770002
10511313131397
11187934a29572
1283119896a85
13392a7bc0173
141aa67924a45
15d478e27132
hex770ca33785

511313131397 has 2 divisors, whose sum is σ = 511313131398. Its totient is φ = 511313131396.

The previous prime is 511313131367. The next prime is 511313131429. The reversal of 511313131397 is 793131313115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 491862366241 + 19450765156 = 701329^2 + 139466^2 .

It is a cyclic number.

It is not a de Polignac number, because 511313131397 - 28 = 511313131141 is a prime.

It is a super-2 number, since 2×5113131313972 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 511313131397.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (511313131367) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255656565698 + 255656565699.

It is an arithmetic number, because the mean of its divisors is an integer number (255656565699).

Almost surely, 2511313131397 is an apocalyptic number.

It is an amenable number.

511313131397 is a deficient number, since it is larger than the sum of its proper divisors (1).

511313131397 is an equidigital number, since it uses as much as digits as its factorization.

511313131397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 25515, while the sum is 38.

The spelling of 511313131397 in words is "five hundred eleven billion, three hundred thirteen million, one hundred thirty-one thousand, three hundred ninety-seven".