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511313135053 = 7811839107351
BaseRepresentation
bin1110111000011001010…
…00110100010111001101
31210212210021212112000111
413130030220310113031
531334132130310203
61030521035000021
751640546636360
oct7341450642715
91725707775014
10511313135053
11187934a31296
1283119899011
13392a7bc1a26
141aa679260d7
15d478e2826d
hex770ca345cd

511313135053 has 16 divisors (see below), whose sum is σ = 585781217280. Its totient is φ = 437202198000.

The previous prime is 511313135051. The next prime is 511313135143. The reversal of 511313135053 is 350531313115.

It is a cyclic number.

It is not a de Polignac number, because 511313135053 - 21 = 511313135051 is a prime.

It is a super-2 number, since 2×5113131350532 (a number of 24 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (511313135051) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4709328 + ... + 4816678.

It is an arithmetic number, because the mean of its divisors is an integer number (36611326080).

Almost surely, 2511313135053 is an apocalyptic number.

It is an amenable number.

511313135053 is a deficient number, since it is larger than the sum of its proper divisors (74468082227).

511313135053 is a wasteful number, since it uses less digits than its factorization.

511313135053 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 109008.

The product of its (nonzero) digits is 10125, while the sum is 31.

Adding to 511313135053 its reverse (350531313115), we get a palindrome (861844448168).

The spelling of 511313135053 in words is "five hundred eleven billion, three hundred thirteen million, one hundred thirty-five thousand, fifty-three".

Divisors: 1 7 811 839 5677 5873 107351 680429 751457 4763003 87061661 90067489 609431627 630472423 73044733579 511313135053