Base | Representation |
---|---|
bin | 1110111000011001010… |
… | …00110100010111001101 |
3 | 1210212210021212112000111 |
4 | 13130030220310113031 |
5 | 31334132130310203 |
6 | 1030521035000021 |
7 | 51640546636360 |
oct | 7341450642715 |
9 | 1725707775014 |
10 | 511313135053 |
11 | 187934a31296 |
12 | 83119899011 |
13 | 392a7bc1a26 |
14 | 1aa679260d7 |
15 | d478e2826d |
hex | 770ca345cd |
511313135053 has 16 divisors (see below), whose sum is σ = 585781217280. Its totient is φ = 437202198000.
The previous prime is 511313135051. The next prime is 511313135143. The reversal of 511313135053 is 350531313115.
It is a cyclic number.
It is not a de Polignac number, because 511313135053 - 21 = 511313135051 is a prime.
It is a super-2 number, since 2×5113131350532 (a number of 24 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (511313135051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4709328 + ... + 4816678.
It is an arithmetic number, because the mean of its divisors is an integer number (36611326080).
Almost surely, 2511313135053 is an apocalyptic number.
It is an amenable number.
511313135053 is a deficient number, since it is larger than the sum of its proper divisors (74468082227).
511313135053 is a wasteful number, since it uses less digits than its factorization.
511313135053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 109008.
The product of its (nonzero) digits is 10125, while the sum is 31.
Adding to 511313135053 its reverse (350531313115), we get a palindrome (861844448168).
The spelling of 511313135053 in words is "five hundred eleven billion, three hundred thirteen million, one hundred thirty-five thousand, fifty-three".
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