51131433 has 4 divisors (see below), whose sum is σ = 68175248. Its totient is φ = 34087620.

The previous prime is 51131417. The next prime is 51131449. The reversal of 51131433 is 33413115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (51131417) and next prime (51131449).

It is not a de Polignac number, because 51131433 - 2⁴ = 51131417 is a prime.

It is a super-2 number, since 2×51131433² = 5228846881266978, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51131453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8521903 + ... + 8521908.

It is an arithmetic number, because the mean of its divisors is an integer number (17043812).

Almost surely, 2^51131433 is an apocalyptic number.

It is an amenable number.

51131433 is a deficient number, since it is larger than the sum of its proper divisors (17043815).

51131433 is a wasteful number, since it uses less digits than its factorization.

51131433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17043814.

The product of its digits is 540, while the sum is 21.

The square root of 51131433 is about 7150.6246580281. The cubic root of 51131433 is about 371.1612723148.

Adding to 51131433 its reverse (33413115), we get a palindrome (84544548).

The spelling of 51131433 in words is "fifty-one million, one hundred thirty-one thousand, four hundred thirty-three".