Base | Representation |
---|---|
bin | 10111010000000111110101… |
… | …11001010000011011111010 |
3 | 20201001010100011001002102200 |
4 | 23220003322321100123322 |
5 | 23200214303000130424 |
6 | 300425253053211030 |
7 | 13525062143653224 |
oct | 1350037271203372 |
9 | 221033304032380 |
10 | 51131500005114 |
11 | 15323824837161 |
12 | 5899763a90a76 |
13 | 226b8ab587a19 |
14 | c8aac6421414 |
15 | 5da0aac858c9 |
hex | 2e80fae506fa |
51131500005114 has 24 divisors (see below), whose sum is σ = 111016200447360. Its totient is φ = 17008251216648.
The previous prime is 51131500005109. The next prime is 51131500005133. The reversal of 51131500005114 is 41150000513115.
51131500005114 is a `hidden beast` number, since 5 + 11 + 31 + 500 + 0 + 0 + 5 + 114 = 666.
It is a super-2 number, since 2×511315000051142 (a number of 28 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2965167672 + ... + 2965184915.
It is an arithmetic number, because the mean of its divisors is an integer number (4625675018640).
Almost surely, 251131500005114 is an apocalyptic number.
51131500005114 is an abundant number, since it is smaller than the sum of its proper divisors (59884700442246).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51131500005114 is a wasteful number, since it uses less digits than its factorization.
51131500005114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5930353074 (or 5930353071 counting only the distinct ones).
The product of its (nonzero) digits is 1500, while the sum is 27.
Adding to 51131500005114 its reverse (41150000513115), we get a palindrome (92281500518229).
The spelling of 51131500005114 in words is "fifty-one trillion, one hundred thirty-one billion, five hundred million, five thousand, one hundred fourteen".
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