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51132020411 = 192691158969
BaseRepresentation
bin101111100111101101…
…001011011010111011
311212222110220202200202
4233213231023122323
51314204244123121
635253440352415
73460046000543
oct574755133273
9155873822622
1051132020411
111a75976880a
129ab001570b
134a8b4521a4
142690c06323
1514e3e5340b
hexbe7b4b6bb

51132020411 has 4 divisors (see below), whose sum is σ = 53823179400. Its totient is φ = 48440861424.

The previous prime is 51132020273. The next prime is 51132020417. The reversal of 51132020411 is 11402023115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 51132020411 - 210 = 51132019387 is a prime.

It is a super-2 number, since 2×511320204112 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51132020417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1345579466 + ... + 1345579503.

It is an arithmetic number, because the mean of its divisors is an integer number (13455794850).

Almost surely, 251132020411 is an apocalyptic number.

51132020411 is a deficient number, since it is larger than the sum of its proper divisors (2691158989).

51132020411 is a wasteful number, since it uses less digits than its factorization.

51132020411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2691158988.

The product of its (nonzero) digits is 240, while the sum is 20.

Adding to 51132020411 its reverse (11402023115), we get a palindrome (62534043526).

The spelling of 51132020411 in words is "fifty-one billion, one hundred thirty-two million, twenty thousand, four hundred eleven".

Divisors: 1 19 2691158969 51132020411