Base | Representation |
---|---|
bin | 10111010000001100101100… |
… | …10001011001010101100011 |
3 | 20201001101001211012001211020 |
4 | 23220012112101121111203 |
5 | 23200240122320122012 |
6 | 300430403454020523 |
7 | 13525213556241552 |
oct | 1350062621312543 |
9 | 221041054161736 |
10 | 51134106801507 |
11 | 15324942253944 |
12 | 589a170aa7743 |
13 | 226bc0566a2b2 |
14 | c8ac92711d99 |
15 | 5da1aea59a8c |
hex | 2e8196459563 |
51134106801507 has 16 divisors (see below), whose sum is σ = 70583249740800. Its totient is φ = 32907055609152.
The previous prime is 51134106801469. The next prime is 51134106801517. The reversal of 51134106801507 is 70510860143115.
It is not a de Polignac number, because 51134106801507 - 224 = 51134090024291 is a prime.
It is a super-2 number, since 2×511341068015072 (a number of 28 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (51134106801517) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2483916007 + ... + 2483936592.
It is an arithmetic number, because the mean of its divisors is an integer number (4411453108800).
Almost surely, 251134106801507 is an apocalyptic number.
51134106801507 is a deficient number, since it is larger than the sum of its proper divisors (19449142939293).
51134106801507 is a wasteful number, since it uses less digits than its factorization.
51134106801507 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4967852722.
The product of its (nonzero) digits is 100800, while the sum is 42.
The spelling of 51134106801507 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred six million, eight hundred one thousand, five hundred seven".
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