Base | Representation |
---|---|
bin | 10111010000001100101100… |
… | …10001011001010101101101 |
3 | 20201001101001211012001211121 |
4 | 23220012112101121111231 |
5 | 23200240122320122032 |
6 | 300430403454020541 |
7 | 13525213556241565 |
oct | 1350062621312555 |
9 | 221041054161747 |
10 | 51134106801517 |
11 | 15324942253953 |
12 | 589a170aa7751 |
13 | 226bc0566a2bc |
14 | c8ac92711da5 |
15 | 5da1aea59a97 |
hex | 2e819645956d |
51134106801517 has 2 divisors, whose sum is σ = 51134106801518. Its totient is φ = 51134106801516.
The previous prime is 51134106801469. The next prime is 51134106801529. The reversal of 51134106801517 is 71510860143115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 47229139543716 + 3904967257801 = 6872346^2 + 1976099^2 .
It is a cyclic number.
It is not a de Polignac number, because 51134106801517 - 219 = 51134106277229 is a prime.
It is a super-2 number, since 2×511341068015172 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (51134106801317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25567053400758 + 25567053400759.
It is an arithmetic number, because the mean of its divisors is an integer number (25567053400759).
Almost surely, 251134106801517 is an apocalyptic number.
It is an amenable number.
51134106801517 is a deficient number, since it is larger than the sum of its proper divisors (1).
51134106801517 is an equidigital number, since it uses as much as digits as its factorization.
51134106801517 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 100800, while the sum is 43.
The spelling of 51134106801517 in words is "fifty-one trillion, one hundred thirty-four billion, one hundred six million, eight hundred one thousand, five hundred seventeen".
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