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51134331 = 317044777
BaseRepresentation
bin1100001100001…
…1111101111011
310120012220010010
43003003331323
5101042244311
65023553003
71160430453
oct303037573
9116186103
1051134331
1126955a86
121515b763
13a794801
146b10d63
154750da6
hex30c3f7b

51134331 has 4 divisors (see below), whose sum is σ = 68179112. Its totient is φ = 34089552.

The previous prime is 51134311. The next prime is 51134357. The reversal of 51134331 is 13343115.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 51134331 - 27 = 51134203 is a prime.

It is a super-2 number, since 2×511343312 = 5229439613635122, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 51134298 and 51134307.

It is not an unprimeable number, because it can be changed into a prime (51134311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8522386 + ... + 8522391.

It is an arithmetic number, because the mean of its divisors is an integer number (17044778).

Almost surely, 251134331 is an apocalyptic number.

51134331 is a deficient number, since it is larger than the sum of its proper divisors (17044781).

51134331 is a wasteful number, since it uses less digits than its factorization.

51134331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17044780.

The product of its digits is 540, while the sum is 21.

The square root of 51134331 is about 7150.8272947960. The cubic root of 51134331 is about 371.1682843424.

Adding to 51134331 its reverse (13343115), we get a palindrome (64477446).

The spelling of 51134331 in words is "fifty-one million, one hundred thirty-four thousand, three hundred thirty-one".

Divisors: 1 3 17044777 51134331