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5113435153 = 44926594283
BaseRepresentation
bin1001100001100100…
…01101010000010001
3111012100211102100011
410300302031100101
540433014411103
62203222354521
7240500324131
oct46062152021
914170742304
105113435153
112194445572
12ba858ba41
136364c7698
1436718cac1
151eddb1d6d
hex130c8d411

5113435153 has 8 divisors (see below), whose sum is σ = 5127948000. Its totient is φ = 5098937088.

The previous prime is 5113435147. The next prime is 5113435189. The reversal of 5113435153 is 3515343115.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5113435153 is a prime.

It is a super-2 number, since 2×51134351532 = 52294438127872266818, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5113435753) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1191750 + ... + 1196032.

It is an arithmetic number, because the mean of its divisors is an integer number (640993500).

Almost surely, 25113435153 is an apocalyptic number.

It is an amenable number.

5113435153 is a deficient number, since it is larger than the sum of its proper divisors (14512847).

5113435153 is a wasteful number, since it uses less digits than its factorization.

5113435153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7391.

The product of its digits is 13500, while the sum is 31.

The square root of 5113435153 is about 71508.2873029413. The cubic root of 5113435153 is about 1722.8107945593.

Adding to 5113435153 its reverse (3515343115), we get a palindrome (8628778268).

The spelling of 5113435153 in words is "five billion, one hundred thirteen million, four hundred thirty-five thousand, one hundred fifty-three".

Divisors: 1 449 2659 4283 1193891 1923067 11388497 5113435153