Base | Representation |
---|---|
bin | 101111100111111000… |
… | …100011111010110001 |
3 | 11212222200112100212112 |
4 | 233213320203322301 |
5 | 1314211030114322 |
6 | 35254024335105 |
7 | 3460113236204 |
oct | 574770437261 |
9 | 155880470775 |
10 | 51135004337 |
11 | 1a76041666a |
12 | 9ab1014495 |
13 | 4a8bc58421 |
14 | 269138193b |
15 | 14e43425e2 |
hex | be7e23eb1 |
51135004337 has 4 divisors (see below), whose sum is σ = 51399952740. Its totient is φ = 50870055936.
The previous prime is 51135004231. The next prime is 51135004343. The reversal of 51135004337 is 73340053115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 34551746161 + 16583258176 = 185881^2 + 128776^2 .
It is a cyclic number.
It is not a de Polignac number, because 51135004337 - 222 = 51130810033 is a prime.
It is a super-2 number, since 2×511350043372 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51135004937) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132473912 + ... + 132474297.
It is an arithmetic number, because the mean of its divisors is an integer number (12849988185).
Almost surely, 251135004337 is an apocalyptic number.
It is an amenable number.
51135004337 is a deficient number, since it is larger than the sum of its proper divisors (264948403).
51135004337 is a wasteful number, since it uses less digits than its factorization.
51135004337 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 264948402.
The product of its (nonzero) digits is 18900, while the sum is 32.
The spelling of 51135004337 in words is "fifty-one billion, one hundred thirty-five million, four thousand, three hundred thirty-seven".
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