Base | Representation |
---|---|
bin | 100101001101001010111… |
… | …0010011100001011001011 |
3 | 200002211220021202102220212 |
4 | 1022122111302130023023 |
5 | 1132234444133010102 |
6 | 14513042012111335 |
7 | 1035303615526634 |
oct | 112322562341313 |
9 | 20084807672825 |
10 | 5113524110027 |
11 | 16a16a70616a3 |
12 | 6a7050a6554b |
13 | 2b128471c878 |
14 | 1396d2a0288b |
15 | 8d033dd9c52 |
hex | 4a695c9c2cb |
5113524110027 has 2 divisors, whose sum is σ = 5113524110028. Its totient is φ = 5113524110026.
The previous prime is 5113524109979. The next prime is 5113524110033. The reversal of 5113524110027 is 7200114253115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 5113524110027 - 216 = 5113524044491 is a prime.
It is a super-2 number, since 2×51135241100272 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5113524109975 and 5113524110002.
It is not a weakly prime, because it can be changed into another prime (5113524110627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2556762055013 + 2556762055014.
It is an arithmetic number, because the mean of its divisors is an integer number (2556762055014).
Almost surely, 25113524110027 is an apocalyptic number.
5113524110027 is a deficient number, since it is larger than the sum of its proper divisors (1).
5113524110027 is an equidigital number, since it uses as much as digits as its factorization.
5113524110027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 32.
The spelling of 5113524110027 in words is "five trillion, one hundred thirteen billion, five hundred twenty-four million, one hundred ten thousand, twenty-seven".
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