Base | Representation |
---|---|
bin | 10111010000011000101010… |
… | …11000110011001010110011 |
3 | 20201001222122202212201101011 |
4 | 23220030111120303022303 |
5 | 23200341303302303201 |
6 | 300433345344051351 |
7 | 13525532055123553 |
oct | 1350142530631263 |
9 | 221058582781334 |
10 | 51140534416051 |
11 | 153276404a0883 |
12 | 589b465603b57 |
13 | 226c6bb1c5902 |
14 | c8b302233163 |
15 | 5da438ead151 |
hex | 2e83156332b3 |
51140534416051 has 8 divisors (see below), whose sum is σ = 54308532125520. Its totient is φ = 48020175770112.
The previous prime is 51140534416019. The next prime is 51140534416061. The reversal of 51140534416051 is 15061443504115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 51140534416051 - 25 = 51140534416019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 51140534415995 and 51140534416013.
It is not an unprimeable number, because it can be changed into a prime (51140534416061) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11909763670 + ... + 11909767963.
It is an arithmetic number, because the mean of its divisors is an integer number (6788566515690).
Almost surely, 251140534416051 is an apocalyptic number.
51140534416051 is a deficient number, since it is larger than the sum of its proper divisors (3167997709469).
51140534416051 is a wasteful number, since it uses less digits than its factorization.
51140534416051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23819531765.
The product of its (nonzero) digits is 144000, while the sum is 40.
The spelling of 51140534416051 in words is "fifty-one trillion, one hundred forty billion, five hundred thirty-four million, four hundred sixteen thousand, fifty-one".
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