Base | Representation |
---|---|
bin | 1100001100010… |
… | …1100110010011 |
3 | 10120020020021112 |
4 | 3003011212103 |
5 | 101043003021 |
6 | 5024043535 |
7 | 1160456105 |
oct | 303054623 |
9 | 116206245 |
10 | 51141011 |
11 | 2695aaa9 |
12 | 151635ab |
13 | a79786c |
14 | 6b13575 |
15 | 4752d5b |
hex | 30c5993 |
51141011 has 2 divisors, whose sum is σ = 51141012. Its totient is φ = 51141010.
The previous prime is 51140987. The next prime is 51141037. The reversal of 51141011 is 11014115.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-51141011 is a prime.
It is a super-2 number, since 2×511410112 = 5230806012204242, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51143011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25570505 + 25570506.
It is an arithmetic number, because the mean of its divisors is an integer number (25570506).
Almost surely, 251141011 is an apocalyptic number.
51141011 is a deficient number, since it is larger than the sum of its proper divisors (1).
51141011 is an equidigital number, since it uses as much as digits as its factorization.
51141011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
The square root of 51141011 is about 7151.2943583662. The cubic root of 51141011 is about 371.1844463228.
Adding to 51141011 its reverse (11014115), we get a palindrome (62155126).
The spelling of 51141011 in words is "fifty-one million, one hundred forty-one thousand, eleven".
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