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511414350421913 is a prime number
BaseRepresentation
bin111010001001000001110111…
…0101100001001111110011001
32111001202201211101122122210122
41310102003232230021332121
51014013003042202000123
65011404301552523025
7212502316232623061
oct16422035654117631
92431681741578718
10511414350421913
11138a526762a54a4
124943763b250475
1318c49221508193
14904082da083a1
153e1d0da752bc8
hex1d120eeb09f99

511414350421913 has 2 divisors, whose sum is σ = 511414350421914. Its totient is φ = 511414350421912.

The previous prime is 511414350421879. The next prime is 511414350421939. The reversal of 511414350421913 is 319124053414115.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 511380467920729 + 33882501184 = 22613723^2 + 184072^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-511414350421913 is a prime.

It is a super-2 number, since 2×5114143504219132 (a number of 30 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (511414350421963) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 255707175210956 + 255707175210957.

It is an arithmetic number, because the mean of its divisors is an integer number (255707175210957).

Almost surely, 2511414350421913 is an apocalyptic number.

It is an amenable number.

511414350421913 is a deficient number, since it is larger than the sum of its proper divisors (1).

511414350421913 is an equidigital number, since it uses as much as digits as its factorization.

511414350421913 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 259200, while the sum is 44.

The spelling of 511414350421913 in words is "five hundred eleven trillion, four hundred fourteen billion, three hundred fifty million, four hundred twenty-one thousand, nine hundred thirteen".