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5114155433 is a prime number
BaseRepresentation
bin1001100001101001…
…11101000110101001
3111012102012000101012
410300310331012221
540433210433213
62203250033305
7240506414102
oct46064750651
914172160335
105114155433
112194897742
12ba8878835
136366ba49a
143672d93a9
151edea54a8
hex130d3d1a9

5114155433 has 2 divisors, whose sum is σ = 5114155434. Its totient is φ = 5114155432.

The previous prime is 5114155427. The next prime is 5114155451. The reversal of 5114155433 is 3345514115.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3489501184 + 1624654249 = 59072^2 + 40307^2 .

It is a cyclic number.

It is not a de Polignac number, because 5114155433 - 26 = 5114155369 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5114155433.

It is not a weakly prime, because it can be changed into another prime (5114125433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557077716 + 2557077717.

It is an arithmetic number, because the mean of its divisors is an integer number (2557077717).

Almost surely, 25114155433 is an apocalyptic number.

It is an amenable number.

5114155433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5114155433 is an equidigital number, since it uses as much as digits as its factorization.

5114155433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 18000, while the sum is 32.

The square root of 5114155433 is about 71513.3234649320. The cubic root of 5114155433 is about 1722.8916826421.

Adding to 5114155433 its reverse (3345514115), we get a palindrome (8459669548).

The spelling of 5114155433 in words is "five billion, one hundred fourteen million, one hundred fifty-five thousand, four hundred thirty-three".