Base | Representation |
---|---|
bin | 100101001101100000101… |
… | …0000111001000110011001 |
3 | 200002220210010020221211222 |
4 | 1022123001100321012121 |
5 | 1132242442344404423 |
6 | 14513242225501425 |
7 | 1035330653412353 |
oct | 112330120710631 |
9 | 20086703227758 |
10 | 5114253513113 |
11 | 16a1a40863a68 |
12 | 6a72151a1875 |
13 | 2b136c885324 |
14 | 1397618320d3 |
15 | 8d077e693c8 |
hex | 4a6c1439199 |
5114253513113 has 8 divisors (see below), whose sum is σ = 5124210435936. Its totient is φ = 5104297130400.
The previous prime is 5114253513101. The next prime is 5114253513121. The reversal of 5114253513113 is 3113153524115.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5114253513113 - 212 = 5114253509017 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5114253513143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22504070 + ... + 22730192.
It is an arithmetic number, because the mean of its divisors is an integer number (640526304492).
Almost surely, 25114253513113 is an apocalyptic number.
It is an amenable number.
5114253513113 is a deficient number, since it is larger than the sum of its proper divisors (9956922823).
5114253513113 is a wasteful number, since it uses less digits than its factorization.
5114253513113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 270055.
The product of its digits is 27000, while the sum is 35.
The spelling of 5114253513113 in words is "five trillion, one hundred fourteen billion, two hundred fifty-three million, five hundred thirteen thousand, one hundred thirteen".
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