Base | Representation |
---|---|
bin | 1100001100011… |
… | …0000110101011 |
3 | 10120020100010021 |
4 | 3003012012223 |
5 | 101043034313 |
6 | 5024101311 |
7 | 1160465125 |
oct | 303060653 |
9 | 116210107 |
10 | 51143083 |
11 | 26961612 |
12 | 15164837 |
13 | a7987a4 |
14 | 6b14215 |
15 | 475378d |
hex | 30c61ab |
51143083 has 2 divisors, whose sum is σ = 51143084. Its totient is φ = 51143082.
The previous prime is 51143069. The next prime is 51143093. The reversal of 51143083 is 38034115.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 51143083 - 213 = 51134891 is a prime.
It is a super-2 number, since 2×511430832 = 5231229877489778, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51143033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25571541 + 25571542.
It is an arithmetic number, because the mean of its divisors is an integer number (25571542).
Almost surely, 251143083 is an apocalyptic number.
51143083 is a deficient number, since it is larger than the sum of its proper divisors (1).
51143083 is an equidigital number, since it uses as much as digits as its factorization.
51143083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 25.
The square root of 51143083 is about 7151.4392257783. The cubic root of 51143083 is about 371.1894591542.
Adding to 51143083 its reverse (38034115), we get a palindrome (89177198).
The spelling of 51143083 in words is "fifty-one million, one hundred forty-three thousand, eighty-three".
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