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5114398866347 = 19932125659107
BaseRepresentation
bin100101001101100100111…
…1011010111101110101011
3200002221011020202200000002
41022123021323113232223
51132243242102210342
614513304501133215
71035334400036621
oct112331173275653
920087136680002
105114398866347
1116a2005912001
126a72559ba20b
132b1393a18164
14139776c6b511
158d085acbd32
hex4a6c9ed7bab

5114398866347 has 4 divisors (see below), whose sum is σ = 5114424724776. Its totient is φ = 5114373007920.

The previous prime is 5114398866341. The next prime is 5114398866359. The reversal of 5114398866347 is 7436688934115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5114398866347 is a prime.

It is a super-3 number, since 3×51143988663473 (a number of 39 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (5114398866341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12630233 + ... + 13028874.

It is an arithmetic number, because the mean of its divisors is an integer number (1278606181194).

Almost surely, 25114398866347 is an apocalyptic number.

5114398866347 is a deficient number, since it is larger than the sum of its proper divisors (25858429).

5114398866347 is a wasteful number, since it uses less digits than its factorization.

5114398866347 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25858428.

The product of its digits is 104509440, while the sum is 65.

The spelling of 5114398866347 in words is "five trillion, one hundred fourteen billion, three hundred ninety-eight million, eight hundred sixty-six thousand, three hundred forty-seven".

Divisors: 1 199321 25659107 5114398866347