Base | Representation |
---|---|
bin | 10111010000100001110100… |
… | …00101001111000000111001 |
3 | 20201002110100000000210222011 |
4 | 23220100322011033000321 |
5 | 23200431332410332023 |
6 | 300435520523125521 |
7 | 13526064543365446 |
oct | 1350207205170071 |
9 | 221073300023864 |
10 | 51145445011513 |
11 | 15329730393936 |
12 | 58a03b60738a1 |
13 | 226ccc16805b8 |
14 | c8b64a4a09cd |
15 | 5da62515450d |
hex | 2e843a14f039 |
51145445011513 has 2 divisors, whose sum is σ = 51145445011514. Its totient is φ = 51145445011512.
The previous prime is 51145445011471. The next prime is 51145445011517. The reversal of 51145445011513 is 31511054454115.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29388845637904 + 21756599373609 = 5421148^2 + 4664397^2 .
It is a cyclic number.
It is not a de Polignac number, because 51145445011513 - 213 = 51145445003321 is a prime.
It is not a weakly prime, because it can be changed into another prime (51145445011517) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25572722505756 + 25572722505757.
It is an arithmetic number, because the mean of its divisors is an integer number (25572722505757).
Almost surely, 251145445011513 is an apocalyptic number.
It is an amenable number.
51145445011513 is a deficient number, since it is larger than the sum of its proper divisors (1).
51145445011513 is an equidigital number, since it uses as much as digits as its factorization.
51145445011513 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120000, while the sum is 40.
Adding to 51145445011513 its reverse (31511054454115), we get a palindrome (82656499465628).
The spelling of 51145445011513 in words is "fifty-one trillion, one hundred forty-five billion, four hundred forty-five million, eleven thousand, five hundred thirteen".
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