Base | Representation |
---|---|
bin | 1001100001101110… |
… | …01111001100001001 |
3 | 111012110022102011222 |
4 | 10300313033030021 |
5 | 40433334110201 |
6 | 2203310531425 |
7 | 240514455443 |
oct | 46067171411 |
9 | 14173272158 |
10 | 5114753801 |
11 | 2195166263 |
12 | ba8b06b75 |
13 | 636869951 |
14 | 367413493 |
15 | 1ee07291b |
hex | 130dcf309 |
5114753801 has 4 divisors (see below), whose sum is σ = 5179497600. Its totient is φ = 5050010004.
The previous prime is 5114753771. The next prime is 5114753821. The reversal of 5114753801 is 1083574115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 5114753801 - 214 = 5114737417 is a prime.
It is a super-3 number, since 3×51147538013 (a number of 30 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5114753821) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32371781 + ... + 32371938.
It is an arithmetic number, because the mean of its divisors is an integer number (1294874400).
Almost surely, 25114753801 is an apocalyptic number.
It is an amenable number.
5114753801 is a deficient number, since it is larger than the sum of its proper divisors (64743799).
5114753801 is an equidigital number, since it uses as much as digits as its factorization.
5114753801 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 64743798.
The product of its (nonzero) digits is 16800, while the sum is 35.
The square root of 5114753801 is about 71517.5069545912. The cubic root of 5114753801 is about 1722.9588741240.
The spelling of 5114753801 in words is "five billion, one hundred fourteen million, seven hundred fifty-three thousand, eight hundred one".
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