Base | Representation |
---|---|
bin | 101111101000110010… |
… | …111010010011110001 |
3 | 11220000202022111010102 |
4 | 233220302322103301 |
5 | 1314223434103101 |
6 | 35255332242145 |
7 | 3460360244144 |
oct | 575062722361 |
9 | 156022274112 |
10 | 51150300401 |
11 | 1a769013842 |
12 | 9ab6170355 |
13 | 4a92182755 |
14 | 269340405b |
15 | 14e586486b |
hex | be8cba4f1 |
51150300401 has 2 divisors, whose sum is σ = 51150300402. Its totient is φ = 51150300400.
The previous prime is 51150300389. The next prime is 51150300419. The reversal of 51150300401 is 10400305115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 38258968801 + 12891331600 = 195599^2 + 113540^2 .
It is a cyclic number.
It is not a de Polignac number, because 51150300401 - 218 = 51150038257 is a prime.
It is a super-2 number, since 2×511503004012 (a number of 22 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (51150303401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25575150200 + 25575150201.
It is an arithmetic number, because the mean of its divisors is an integer number (25575150201).
Almost surely, 251150300401 is an apocalyptic number.
It is an amenable number.
51150300401 is a deficient number, since it is larger than the sum of its proper divisors (1).
51150300401 is an equidigital number, since it uses as much as digits as its factorization.
51150300401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 20.
Adding to 51150300401 its reverse (10400305115), we get a palindrome (61550605516).
The spelling of 51150300401 in words is "fifty-one billion, one hundred fifty million, three hundred thousand, four hundred one".
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