Base | Representation |
---|---|
bin | 100101001101111000011… |
… | …1001111011100000000001 |
3 | 200002222211211020221100001 |
4 | 1022123300321323200001 |
5 | 1132301112004100001 |
6 | 14513453421200001 |
7 | 1035356530266004 |
oct | 112336071734001 |
9 | 20088754227301 |
10 | 5115052800001 |
11 | 16a2310a58041 |
12 | 6a73b8a00001 |
13 | 2b1469348751 |
14 | 1397d9a5353b |
15 | 8d0c3200001 |
hex | 4a6f0e7b801 |
5115052800001 has 4 divisors (see below), whose sum is σ = 5143312760404. Its totient is φ = 5086792839600.
The previous prime is 5115052799903. The next prime is 5115052800049. The reversal of 5115052800001 is 1000082505115.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 1429516749376 + 3685536050625 = 1195624^2 + 1919775^2 .
It is a cyclic number.
It is not a de Polignac number, because 5115052800001 - 213 = 5115052791809 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5115052800071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14129979930 + ... + 14129980291.
It is an arithmetic number, because the mean of its divisors is an integer number (1285828190101).
Almost surely, 25115052800001 is an apocalyptic number.
It is an amenable number.
5115052800001 is a deficient number, since it is larger than the sum of its proper divisors (28259960403).
5115052800001 is a wasteful number, since it uses less digits than its factorization.
5115052800001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28259960402.
The product of its (nonzero) digits is 2000, while the sum is 28.
The spelling of 5115052800001 in words is "five trillion, one hundred fifteen billion, fifty-two million, eight hundred thousand, one".
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