Base | Representation |
---|---|
bin | 101111101000110101… |
… | …100101101000101001 |
3 | 11220000210122010202020 |
4 | 233220311211220221 |
5 | 1314224124032103 |
6 | 35255355255053 |
7 | 3460366226106 |
oct | 575065455051 |
9 | 156023563666 |
10 | 51151002153 |
11 | 1a769452aa9 |
12 | 9ab644a489 |
13 | 4a92369ca4 |
14 | 2693547aad |
15 | 14e5952753 |
hex | be8d65a29 |
51151002153 has 4 divisors (see below), whose sum is σ = 68201336208. Its totient is φ = 34100668100.
The previous prime is 51151002073. The next prime is 51151002173. The reversal of 51151002153 is 35120015115.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51151002153 - 28 = 51151001897 is a prime.
It is not an unprimeable number, because it can be changed into a prime (51151002173) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8525167023 + ... + 8525167028.
It is an arithmetic number, because the mean of its divisors is an integer number (17050334052).
Almost surely, 251151002153 is an apocalyptic number.
It is an amenable number.
51151002153 is a deficient number, since it is larger than the sum of its proper divisors (17050334055).
51151002153 is a wasteful number, since it uses less digits than its factorization.
51151002153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17050334054.
The product of its (nonzero) digits is 750, while the sum is 24.
Adding to 51151002153 its reverse (35120015115), we get a palindrome (86271017268).
The spelling of 51151002153 in words is "fifty-one billion, one hundred fifty-one million, two thousand, one hundred fifty-three".
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