Base | Representation |
---|---|
bin | 1001100001110010… |
… | …01001001010101001 |
3 | 111012111020210112021 |
4 | 10300321021022221 |
5 | 40434001102132 |
6 | 2203325344441 |
7 | 240521636161 |
oct | 46071111251 |
9 | 14174223467 |
10 | 5115253417 |
11 | 219547766a |
12 | ba9108121 |
13 | 6369b3191 |
14 | 3675035a1 |
15 | 1ee120997 |
hex | 130e492a9 |
5115253417 has 2 divisors, whose sum is σ = 5115253418. Its totient is φ = 5115253416.
The previous prime is 5115253391. The next prime is 5115253477. The reversal of 5115253417 is 7143525115.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5060330496 + 54922921 = 71136^2 + 7411^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5115253417 is a prime.
It is a super-3 number, since 3×51152534173 (a number of 30 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (5115253477) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2557626708 + 2557626709.
It is an arithmetic number, because the mean of its divisors is an integer number (2557626709).
Almost surely, 25115253417 is an apocalyptic number.
It is an amenable number.
5115253417 is a deficient number, since it is larger than the sum of its proper divisors (1).
5115253417 is an equidigital number, since it uses as much as digits as its factorization.
5115253417 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21000, while the sum is 34.
The square root of 5115253417 is about 71520.9998322171. Note that the first 3 decimals coincide. The cubic root of 5115253417 is about 1723.0149726074.
The spelling of 5115253417 in words is "five billion, one hundred fifteen million, two hundred fifty-three thousand, four hundred seventeen".
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