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5115314051 = 33115454121
BaseRepresentation
bin1001100001110010…
…10111111110000011
3111012111100212200222
410300321113332003
540434010022201
62203330533255
7240522311021
oct46071277603
914174325628
105115314051
112195509181
12ba913722b
13636a04963
1436751b711
151ee13391b
hex130e57f83

5115314051 has 4 divisors (see below), whose sum is σ = 5130768504. Its totient is φ = 5099859600.

The previous prime is 5115314023. The next prime is 5115314053. The reversal of 5115314051 is 1504135115.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5115314051 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 5115314051.

It is not an unprimeable number, because it can be changed into a prime (5115314053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7726730 + ... + 7727391.

It is an arithmetic number, because the mean of its divisors is an integer number (1282692126).

Almost surely, 25115314051 is an apocalyptic number.

5115314051 is a deficient number, since it is larger than the sum of its proper divisors (15454453).

5115314051 is a wasteful number, since it uses less digits than its factorization.

5115314051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15454452.

The product of its (nonzero) digits is 1500, while the sum is 26.

The square root of 5115314051 is about 71521.4237204490. The cubic root of 5115314051 is about 1723.0217805384.

Adding to 5115314051 its reverse (1504135115), we get a palindrome (6619449166).

The spelling of 5115314051 in words is "five billion, one hundred fifteen million, three hundred fourteen thousand, fifty-one".

Divisors: 1 331 15454121 5115314051