511532531404313 has 4 divisors (see below), whose sum is σ = 513826399258368. Its totient is φ = 509238663550260.

The previous prime is 511532531404283. The next prime is 511532531404351. The reversal of 511532531404313 is 313404135235115.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 511532531404313 - 2⁴⁶ = 441163787226649 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (511532531404913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1146933926693 + ... + 1146933927138.

It is an arithmetic number, because the mean of its divisors is an integer number (128456599814592).

Almost surely, 2^{511532531404313} is an apocalyptic number.

It is an amenable number.

511532531404313 is a deficient number, since it is larger than the sum of its proper divisors (2293867854055).

511532531404313 is a wasteful number, since it uses less digits than its factorization.

511532531404313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2293867854054.

The product of its (nonzero) digits is 324000, while the sum is 41.

Adding to 511532531404313 its reverse (313404135235115), we get a palindrome (824936666639428).

The spelling of 511532531404313 in words is "five hundred eleven trillion, five hundred thirty-two billion, five hundred thirty-one million, four hundred four thousand, three hundred thirteen".