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51171400457 = 192693231603
BaseRepresentation
bin101111101010000011…
…011001101100001001
311220002020000110221222
4233222003121230021
51314244334303312
635301404411425
73461034504302
oct575203315411
9156066013858
1051171400457
111a779a15601
129b01246b75
134a9665c7a8
1426961377a9
1514e7631672
hexbea0d9b09

51171400457 has 4 divisors (see below), whose sum is σ = 53864632080. Its totient is φ = 48478168836.

The previous prime is 51171400453. The next prime is 51171400471. The reversal of 51171400457 is 75400417115.

51171400457 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51171400457 - 22 = 51171400453 is a prime.

It is a super-3 number, since 3×511714004573 (a number of 33 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51171400453) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1346615783 + ... + 1346615820.

It is an arithmetic number, because the mean of its divisors is an integer number (13466158020).

Almost surely, 251171400457 is an apocalyptic number.

It is an amenable number.

51171400457 is a deficient number, since it is larger than the sum of its proper divisors (2693231623).

51171400457 is a wasteful number, since it uses less digits than its factorization.

51171400457 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2693231622.

The product of its (nonzero) digits is 19600, while the sum is 35.

The spelling of 51171400457 in words is "fifty-one billion, one hundred seventy-one million, four hundred thousand, four hundred fifty-seven".

Divisors: 1 19 2693231603 51171400457