Base | Representation |
---|---|
bin | 100101001111100110010… |
… | …0000100111110100110011 |
3 | 200010100100121000110221210 |
4 | 1022133030200213310303 |
5 | 1132331133202401311 |
6 | 14515303153451203 |
7 | 1035550035624624 |
oct | 112371440476463 |
9 | 20110317013853 |
10 | 5118737153331 |
11 | 16a393175024a |
12 | 6a8066870b03 |
13 | 2b1905751589 |
14 | 139a690bda4b |
15 | 8d23b8c53a6 |
hex | 4a7cc827d33 |
5118737153331 has 4 divisors (see below), whose sum is σ = 6824982871112. Its totient is φ = 3412491435552.
The previous prime is 5118737153303. The next prime is 5118737153377. The reversal of 5118737153331 is 1333517378115.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 5118737153331 - 237 = 4981298199859 is a prime.
It is a super-2 number, since 2×51187371533312 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5118757153331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 853122858886 + ... + 853122858891.
It is an arithmetic number, because the mean of its divisors is an integer number (1706245717778).
Almost surely, 25118737153331 is an apocalyptic number.
5118737153331 is a deficient number, since it is larger than the sum of its proper divisors (1706245717781).
5118737153331 is a wasteful number, since it uses less digits than its factorization.
5118737153331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1706245717780.
The product of its digits is 793800, while the sum is 48.
The spelling of 5118737153331 in words is "five trillion, one hundred eighteen billion, seven hundred thirty-seven million, one hundred fifty-three thousand, three hundred thirty-one".
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