Base | Representation |
---|---|
bin | 101111101011011001… |
… | …010011101011001011 |
3 | 11220010210101121020122 |
4 | 233223121103223023 |
5 | 1314321120421303 |
6 | 35303531213455 |
7 | 3461430066446 |
oct | 575331235313 |
9 | 156123347218 |
10 | 51193920203 |
11 | 1a7906a6a68 |
12 | 9b088a728b |
13 | 4a9b215a9a |
14 | 269911a65d |
15 | 14e95cde38 |
hex | beb653acb |
51193920203 has 2 divisors, whose sum is σ = 51193920204. Its totient is φ = 51193920202.
The previous prime is 51193920179. The next prime is 51193920229. The reversal of 51193920203 is 30202939115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 51193920203 - 226 = 51126811339 is a prime.
It is a super-2 number, since 2×511939202032 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51193920233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25596960101 + 25596960102.
It is an arithmetic number, because the mean of its divisors is an integer number (25596960102).
Almost surely, 251193920203 is an apocalyptic number.
51193920203 is a deficient number, since it is larger than the sum of its proper divisors (1).
51193920203 is an equidigital number, since it uses as much as digits as its factorization.
51193920203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 35.
The spelling of 51193920203 in words is "fifty-one billion, one hundred ninety-three million, nine hundred twenty thousand, two hundred three".
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