Base | Representation |
---|---|
bin | 10011100001111110111011 |
3 | 100122010020002 |
4 | 103201332323 |
5 | 2302314211 |
6 | 301423215 |
7 | 61342625 |
oct | 23417673 |
9 | 10563202 |
10 | 5119931 |
11 | 2987753 |
12 | 186ab0b |
13 | 10a355b |
14 | 973c15 |
15 | 6b203b |
hex | 4e1fbb |
5119931 has 2 divisors, whose sum is σ = 5119932. Its totient is φ = 5119930.
The previous prime is 5119909. The next prime is 5119963. The reversal of 5119931 is 1399115.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5119931 - 210 = 5118907 is a prime.
It is a super-2 number, since 2×51199312 = 52427386889522, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5119894 and 5119903.
It is not a weakly prime, because it can be changed into another prime (5119901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2559965 + 2559966.
It is an arithmetic number, because the mean of its divisors is an integer number (2559966).
Almost surely, 25119931 is an apocalyptic number.
5119931 is a deficient number, since it is larger than the sum of its proper divisors (1).
5119931 is an equidigital number, since it uses as much as digits as its factorization.
5119931 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1215, while the sum is 29.
The square root of 5119931 is about 2262.7264527556. The cubic root of 5119931 is about 172.3540009491.
The spelling of 5119931 in words is "five million, one hundred nineteen thousand, nine hundred thirty-one".
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