Base | Representation |
---|---|
bin | 1001100010010110… |
… | …10001001111011001 |
3 | 111012211012012120211 |
4 | 10301023101033121 |
5 | 40441210130311 |
6 | 2204015251121 |
7 | 240610216342 |
oct | 46113211731 |
9 | 14184165524 |
10 | 5120005081 |
11 | 2198122664 |
12 | baa819aa1 |
13 | 637987c09 |
14 | 367dbd0c9 |
15 | 1ee75d821 |
hex | 1312d13d9 |
5120005081 has 2 divisors, whose sum is σ = 5120005082. Its totient is φ = 5120005080.
The previous prime is 5120004961. The next prime is 5120005133. The reversal of 5120005081 is 1805000215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2991105481 + 2128899600 = 54691^2 + 46140^2 .
It is a cyclic number.
It is not a de Polignac number, because 5120005081 - 217 = 5119874009 is a prime.
It is a super-2 number, since 2×51200050812 = 52428904058931633122, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5120003081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560002540 + 2560002541.
It is an arithmetic number, because the mean of its divisors is an integer number (2560002541).
Almost surely, 25120005081 is an apocalyptic number.
It is an amenable number.
5120005081 is a deficient number, since it is larger than the sum of its proper divisors (1).
5120005081 is an equidigital number, since it uses as much as digits as its factorization.
5120005081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 400, while the sum is 22.
The square root of 5120005081 is about 71554.2107845513. The cubic root of 5120005081 is about 1723.5483221650.
Adding to 5120005081 its reverse (1805000215), we get a palindrome (6925005296).
The spelling of 5120005081 in words is "five billion, one hundred twenty million, five thousand, eighty-one".
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