Base | Representation |
---|---|
bin | 101111101011110010… |
… | …001010011101101001 |
3 | 11220011020122122100011 |
4 | 233223302022131221 |
5 | 1314324302423243 |
6 | 35304323011521 |
7 | 3461536345243 |
oct | 575362123551 |
9 | 156136578304 |
10 | 51200436073 |
11 | 1a794347486 |
12 | 9b0ab09ba1 |
13 | 4a9c687827 |
14 | 2699d35093 |
15 | 14e9e6989d |
hex | bebc8a769 |
51200436073 has 2 divisors, whose sum is σ = 51200436074. Its totient is φ = 51200436072.
The previous prime is 51200436019. The next prime is 51200436109. The reversal of 51200436073 is 37063400215.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 44454770649 + 6745665424 = 210843^2 + 82132^2 .
It is a cyclic number.
It is not a de Polignac number, because 51200436073 - 217 = 51200305001 is a prime.
It is a super-2 number, since 2×512004360732 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (51200433073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25600218036 + 25600218037.
It is an arithmetic number, because the mean of its divisors is an integer number (25600218037).
Almost surely, 251200436073 is an apocalyptic number.
It is an amenable number.
51200436073 is a deficient number, since it is larger than the sum of its proper divisors (1).
51200436073 is an equidigital number, since it uses as much as digits as its factorization.
51200436073 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15120, while the sum is 31.
Adding to 51200436073 its reverse (37063400215), we get a palindrome (88263836288).
The spelling of 51200436073 in words is "fifty-one billion, two hundred million, four hundred thirty-six thousand, seventy-three".
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