51200796980433 has 4 divisors (see below), whose sum is σ = 68267729307248. Its totient is φ = 34133864653620.

The previous prime is 51200796980429. The next prime is 51200796980449. The reversal of 51200796980433 is 33408969700215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 51200796980433 - 2² = 51200796980429 is a prime.

It is a super-2 number, since 2×51200796980433² (a number of 28 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (51200796980413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8533466163403 + ... + 8533466163408.

It is an arithmetic number, because the mean of its divisors is an integer number (17066932326812).

It is a 1-persistent number, because it is pandigital, but 2⋅51200796980433 = 102401593960866 is not.

Almost surely, 2^{51200796980433} is an apocalyptic number.

It is an amenable number.

51200796980433 is a deficient number, since it is larger than the sum of its proper divisors (17066932326815).

51200796980433 is a wasteful number, since it uses less digits than its factorization.

51200796980433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17066932326814.

The product of its (nonzero) digits is 9797760, while the sum is 57.

The spelling of 51200796980433 in words is "fifty-one trillion, two hundred billion, seven hundred ninety-six million, nine hundred eighty thousand, four hundred thirty-three".