Base | Representation |
---|---|
bin | 100101010000001111010… |
… | …0001100100101111011001 |
3 | 200010110220111011120100021 |
4 | 1022200132201210233121 |
5 | 1132341442430301203 |
6 | 14520051505510441 |
7 | 1035626114362654 |
oct | 112403641445731 |
9 | 20113814146307 |
10 | 5120113134553 |
11 | 16a447842430a |
12 | 6a838b642421 |
13 | 2b1a94840651 |
14 | 139b59b3c89b |
15 | 8d2bc5c35bd |
hex | 4a81e864bd9 |
5120113134553 has 4 divisors (see below), whose sum is σ = 5258494570660. Its totient is φ = 4981731698448.
The previous prime is 5120113134533. The next prime is 5120113134611. The reversal of 5120113134553 is 3554313110215.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 2155972432329 + 2964140702224 = 1468323^2 + 1721668^2 .
It is a cyclic number.
It is not a de Polignac number, because 5120113134553 - 237 = 4982674181081 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5120113134533) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 69190717998 + ... + 69190718071.
It is an arithmetic number, because the mean of its divisors is an integer number (1314623642665).
Almost surely, 25120113134553 is an apocalyptic number.
It is an amenable number.
5120113134553 is a deficient number, since it is larger than the sum of its proper divisors (138381436107).
5120113134553 is a wasteful number, since it uses less digits than its factorization.
5120113134553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138381436106.
The product of its (nonzero) digits is 27000, while the sum is 34.
Adding to 5120113134553 its reverse (3554313110215), we get a palindrome (8674426244768).
The spelling of 5120113134553 in words is "five trillion, one hundred twenty billion, one hundred thirteen million, one hundred thirty-four thousand, five hundred fifty-three".
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