51206131113 has 4 divisors (see below), whose sum is σ = 68274841488. Its totient is φ = 34137420740.

The previous prime is 51206131091. The next prime is 51206131117. The reversal of 51206131113 is 31113160215.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 51206131113 - 2³³ = 42616196521 is a prime.

It is not an unprimeable number, because it can be changed into a prime (51206131117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8534355183 + ... + 8534355188.

It is an arithmetic number, because the mean of its divisors is an integer number (17068710372).

Almost surely, 2^51206131113 is an apocalyptic number.

It is an amenable number.

51206131113 is a deficient number, since it is larger than the sum of its proper divisors (17068710375).

51206131113 is a wasteful number, since it uses less digits than its factorization.

51206131113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17068710374.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 51206131113 its reverse (31113160215), we get a palindrome (82319291328).

The spelling of 51206131113 in words is "fifty-one billion, two hundred six million, one hundred thirty-one thousand, one hundred thirteen".