Base | Representation |
---|---|
bin | 100101010000101110001… |
… | …0110011011101101001001 |
3 | 200010120120202222011220011 |
4 | 1022201130112123231021 |
5 | 1132401104000320403 |
6 | 14520342442031521 |
7 | 1035663611116300 |
oct | 112413426335511 |
9 | 20116522864804 |
10 | 5121150401353 |
11 | 16a495a9911a8 |
12 | 6a861aaa85a1 |
13 | 2b1bcb6c829c |
14 | 139c177cb437 |
15 | 8d32d6b6a6d |
hex | 4a85c59bb49 |
5121150401353 has 6 divisors (see below), whose sum is σ = 5957256589386. Its totient is φ = 4389557486832.
The previous prime is 5121150401291. The next prime is 5121150401371. The reversal of 5121150401353 is 3531040511215.
It can be written as a sum of positive squares in only one way, i.e., 3884001399369 + 1237149001984 = 1970787^2 + 1112272^2 .
It is not a de Polignac number, because 5121150401353 - 221 = 5121148304201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (5121150201353) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 52256636700 + ... + 52256636797.
It is an arithmetic number, because the mean of its divisors is an integer number (992876098231).
Almost surely, 25121150401353 is an apocalyptic number.
It is an amenable number.
5121150401353 is a deficient number, since it is larger than the sum of its proper divisors (836106188033).
5121150401353 is a wasteful number, since it uses less digits than its factorization.
5121150401353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 104513273511 (or 104513273504 counting only the distinct ones).
The product of its (nonzero) digits is 9000, while the sum is 31.
Adding to 5121150401353 its reverse (3531040511215), we get a palindrome (8652190912568).
The spelling of 5121150401353 in words is "five trillion, one hundred twenty-one billion, one hundred fifty million, four hundred one thousand, three hundred fifty-three".
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