Base | Representation |
---|---|
bin | 100101010000110001111… |
… | …0101001001100011110011 |
3 | 200010120220112002212110002 |
4 | 1022201203311021203303 |
5 | 1132401333112102003 |
6 | 14520403123500215 |
7 | 1035666663565133 |
oct | 112414365114363 |
9 | 20116815085402 |
10 | 5121275894003 |
11 | 16a4a14804735 |
12 | 6a8654b2766b |
13 | 2b1c1b6c62a9 |
14 | 139c2a336ac3 |
15 | 8d339704a88 |
hex | 4a863d498f3 |
5121275894003 has 2 divisors, whose sum is σ = 5121275894004. Its totient is φ = 5121275894002.
The previous prime is 5121275893999. The next prime is 5121275894039. The reversal of 5121275894003 is 3004985721215.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5121275894003 - 22 = 5121275893999 is a prime.
It is not a weakly prime, because it can be changed into another prime (5121275894303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2560637947001 + 2560637947002.
It is an arithmetic number, because the mean of its divisors is an integer number (2560637947002).
Almost surely, 25121275894003 is an apocalyptic number.
5121275894003 is a deficient number, since it is larger than the sum of its proper divisors (1).
5121275894003 is an equidigital number, since it uses as much as digits as its factorization.
5121275894003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 604800, while the sum is 47.
The spelling of 5121275894003 in words is "five trillion, one hundred twenty-one billion, two hundred seventy-five million, eight hundred ninety-four thousand, three".
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