Base | Representation |
---|---|
bin | 111010001110001111001000… |
… | …0000111010101110111011111 |
3 | 2111011022011002212100021210121 |
4 | 1310130132100013111313133 |
5 | 1014111214241423021143 |
6 | 5013113141301215411 |
7 | 212605113252405103 |
oct | 16434362007256737 |
9 | 2434264085307717 |
10 | 512130023251423 |
11 | 1391a9139a17955 |
12 | 49532290701567 |
13 | 18c9b866a09425 |
14 | 9067322637903 |
15 | 3e31a257267ed |
hex | 1d1c7901d5ddf |
512130023251423 has 16 divisors (see below), whose sum is σ = 530722543750560. Its totient is φ = 493599790028800.
The previous prime is 512130023251291. The next prime is 512130023251471. The reversal of 512130023251423 is 324152320031215.
It is a cyclic number.
It is not a de Polignac number, because 512130023251423 - 213 = 512130023243231 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (512130023258423) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 300132903 + ... + 301834423.
It is an arithmetic number, because the mean of its divisors is an integer number (33170158984410).
Almost surely, 2512130023251423 is an apocalyptic number.
512130023251423 is a deficient number, since it is larger than the sum of its proper divisors (18592520499137).
512130023251423 is a wasteful number, since it uses less digits than its factorization.
512130023251423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1719818.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 512130023251423 its reverse (324152320031215), we get a palindrome (836282343282638).
The spelling of 512130023251423 in words is "five hundred twelve trillion, one hundred thirty billion, twenty-three million, two hundred fifty-one thousand, four hundred twenty-three".
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