Base | Representation |
---|---|
bin | 1110111001111011001… |
… | …11010000101100100011 |
3 | 1210221220112222221200212 |
4 | 13130331213100230203 |
5 | 31342323002413103 |
6 | 1031134350204335 |
7 | 52000115030336 |
oct | 7347547205443 |
9 | 1727815887625 |
10 | 512134810403 |
11 | 188216827127 |
12 | 83308ab36ab |
13 | 393a91c3768 |
14 | 1ab04ad461d |
15 | d4c61327d8 |
hex | 773d9d0b23 |
512134810403 has 8 divisors (see below), whose sum is σ = 523641554928. Its totient is φ = 500696355744.
The previous prime is 512134810399. The next prime is 512134810409. The reversal of 512134810403 is 304018431215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 512134810403 - 22 = 512134810399 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 512134810403.
It is not an unprimeable number, because it can be changed into a prime (512134810409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17057300 + ... + 17087297.
It is an arithmetic number, because the mean of its divisors is an integer number (65455194366).
Almost surely, 2512134810403 is an apocalyptic number.
512134810403 is a gapful number since it is divisible by the number (53) formed by its first and last digit.
512134810403 is a deficient number, since it is larger than the sum of its proper divisors (11506744525).
512134810403 is a wasteful number, since it uses less digits than its factorization.
512134810403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 34144933.
The product of its (nonzero) digits is 11520, while the sum is 32.
The spelling of 512134810403 in words is "five hundred twelve billion, one hundred thirty-four million, eight hundred ten thousand, four hundred three".
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