Base | Representation |
---|---|
bin | 10111010010100000101001… |
… | …11100011110100010010110 |
3 | 20201022222002202110120112000 |
4 | 23221100110330132202112 |
5 | 23203040313101414132 |
6 | 300531102013540130 |
7 | 13534025204423103 |
oct | 1351202474364226 |
9 | 221288082416460 |
10 | 51213541435542 |
11 | 153555a5008122 |
12 | 58b163b4a4646 |
13 | 2276554611825 |
14 | c90a6a35baaa |
15 | 5dc2ad59c87c |
hex | 2e9414f1e896 |
51213541435542 has 16 divisors (see below), whose sum is σ = 113807869856880. Its totient is φ = 17071180478496.
The previous prime is 51213541435477. The next prime is 51213541435543. The reversal of 51213541435542 is 24553414531215.
51213541435542 is a `hidden beast` number, since 5 + 1 + 2 + 1 + 3 + 54 + 1 + 43 + 554 + 2 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (51213541435543) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 474199457683 + ... + 474199457790.
It is an arithmetic number, because the mean of its divisors is an integer number (7112991866055).
Almost surely, 251213541435542 is an apocalyptic number.
51213541435542 is an abundant number, since it is smaller than the sum of its proper divisors (62594328421338).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
51213541435542 is a wasteful number, since it uses less digits than its factorization.
51213541435542 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 948398915484 (or 948398915478 counting only the distinct ones).
The product of its digits is 1440000, while the sum is 45.
Adding to 51213541435542 its reverse (24553414531215), we get a palindrome (75766955966757).
The spelling of 51213541435542 in words is "fifty-one trillion, two hundred thirteen billion, five hundred forty-one million, four hundred thirty-five thousand, five hundred forty-two".
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