Base | Representation |
---|---|
bin | 100101010000110110100… |
… | …0100111010101010000011 |
3 | 200010121022100000012100021 |
4 | 1022201231010322222003 |
5 | 1132402142320202321 |
6 | 14520430344434311 |
7 | 1036003556264020 |
oct | 112415504725203 |
9 | 20117270005307 |
10 | 5121431022211 |
11 | 16a4a94329869 |
12 | 6a8698a78997 |
13 | 2b1c4489c42a |
14 | 139c42b98547 |
15 | 8d348148941 |
hex | 4a86d13aa83 |
5121431022211 has 8 divisors (see below), whose sum is σ = 6161120026880. Its totient is φ = 4158756017928.
The previous prime is 5121431022209. The next prime is 5121431022223. The reversal of 5121431022211 is 1122201341215.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5121431022211 - 21 = 5121431022209 is a prime.
It is not an unprimeable number, because it can be changed into a prime (5121431022241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19253499951 + ... + 19253500216.
It is an arithmetic number, because the mean of its divisors is an integer number (770140003360).
Almost surely, 25121431022211 is an apocalyptic number.
5121431022211 is a deficient number, since it is larger than the sum of its proper divisors (1039689004669).
5121431022211 is a wasteful number, since it uses less digits than its factorization.
5121431022211 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 38507000193.
The product of its (nonzero) digits is 960, while the sum is 25.
Adding to 5121431022211 its reverse (1122201341215), we get a palindrome (6243632363426).
The spelling of 5121431022211 in words is "five trillion, one hundred twenty-one billion, four hundred thirty-one million, twenty-two thousand, two hundred eleven".
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