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512215412131 is a prime number
BaseRepresentation
bin1110111010000100110…
…10101110110110100011
31210222010011122221111001
413131002122232312203
531343004121142011
61031150345532431
752002114110653
oct7350232566643
91728104587431
10512215412131
11188258279425
128332baa4117
13393bcb049a7
141ab116b6363
15d4cd2547c1
hex77426aeda3

512215412131 has 2 divisors, whose sum is σ = 512215412132. Its totient is φ = 512215412130.

The previous prime is 512215412099. The next prime is 512215412213. The reversal of 512215412131 is 131214512215.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 512215412131 - 25 = 512215412099 is a prime.

It is a super-2 number, since 2×5122154121312 (a number of 24 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 512215412131.

It is not a weakly prime, because it can be changed into another prime (512215412431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 256107706065 + 256107706066.

It is an arithmetic number, because the mean of its divisors is an integer number (256107706066).

Almost surely, 2512215412131 is an apocalyptic number.

512215412131 is a deficient number, since it is larger than the sum of its proper divisors (1).

512215412131 is an equidigital number, since it uses as much as digits as its factorization.

512215412131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2400, while the sum is 28.

Adding to 512215412131 its reverse (131214512215), we get a palindrome (643429924346).

The spelling of 512215412131 in words is "five hundred twelve billion, two hundred fifteen million, four hundred twelve thousand, one hundred thirty-one".