Base | Representation |
---|---|
bin | 100101010001010100001… |
… | …0111001000011110001001 |
3 | 200010200212122120200110102 |
4 | 1022202220113020132021 |
5 | 1132411211431400004 |
6 | 14521113155055145 |
7 | 1036040324433431 |
oct | 112425027103611 |
9 | 20120778520412 |
10 | 5122425653129 |
11 | 16a5454815794 |
12 | 6a8915ba14b5 |
13 | 2b2072979835 |
14 | 139cd8d092c1 |
15 | 8d3a561911e |
hex | 4a8a85c8789 |
5122425653129 has 2 divisors, whose sum is σ = 5122425653130. Its totient is φ = 5122425653128.
The previous prime is 5122425653119. The next prime is 5122425653141. The reversal of 5122425653129 is 9213565242215.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3381406099600 + 1741019553529 = 1838860^2 + 1319477^2 .
It is a cyclic number.
It is not a de Polignac number, because 5122425653129 - 28 = 5122425652873 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (5122425653119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2561212826564 + 2561212826565.
It is an arithmetic number, because the mean of its divisors is an integer number (2561212826565).
Almost surely, 25122425653129 is an apocalyptic number.
It is an amenable number.
5122425653129 is a deficient number, since it is larger than the sum of its proper divisors (1).
5122425653129 is an equidigital number, since it uses as much as digits as its factorization.
5122425653129 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1296000, while the sum is 47.
The spelling of 5122425653129 in words is "five trillion, one hundred twenty-two billion, four hundred twenty-five million, six hundred fifty-three thousand, one hundred twenty-nine".
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