Base | Representation |
---|---|
bin | 1110111010001000001… |
… | …00110010001101100001 |
3 | 1210222012002222101022112 |
4 | 13131010010302031201 |
5 | 31343033230310103 |
6 | 1031153221445105 |
7 | 52002602320340 |
oct | 7350404621541 |
9 | 1728162871275 |
10 | 512243213153 |
11 | 188271a37781 |
12 | 83339270795 |
13 | 393c57b9ab9 |
14 | 1ab15271b57 |
15 | d4d08e6cd8 |
hex | 7744132361 |
512243213153 has 16 divisors (see below), whose sum is σ = 594677873664. Its totient is φ = 432143895120.
The previous prime is 512243213113. The next prime is 512243213177. The reversal of 512243213153 is 351312342215.
It is not a de Polignac number, because 512243213153 - 218 = 512242951009 is a prime.
It is a super-3 number, since 3×5122432131533 (a number of 36 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (512243213113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 586175 + ... + 1169652.
It is an arithmetic number, because the mean of its divisors is an integer number (37167367104).
Almost surely, 2512243213153 is an apocalyptic number.
It is an amenable number.
512243213153 is a deficient number, since it is larger than the sum of its proper divisors (82434660511).
512243213153 is a wasteful number, since it uses less digits than its factorization.
512243213153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1756492.
The product of its digits is 21600, while the sum is 32.
Adding to 512243213153 its reverse (351312342215), we get a palindrome (863555555368).
The spelling of 512243213153 in words is "five hundred twelve billion, two hundred forty-three million, two hundred thirteen thousand, one hundred fifty-three".
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