51225314024147 has 2 divisors, whose sum is σ = 51225314024148. Its totient is φ = 51225314024146.

The previous prime is 51225314024039. The next prime is 51225314024161. The reversal of 51225314024147 is 74142041352215.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-51225314024147 is a prime.

It is a super-3 number, since 3×51225314024147³ (a number of 42 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (51225314026147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25612657012073 + 25612657012074.

It is an arithmetic number, because the mean of its divisors is an integer number (25612657012074).

Almost surely, 2^{51225314024147} is an apocalyptic number.

51225314024147 is a deficient number, since it is larger than the sum of its proper divisors (1).

51225314024147 is an equidigital number, since it uses as much as digits as its factorization.

51225314024147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 268800, while the sum is 41.

The spelling of 51225314024147 in words is "fifty-one trillion, two hundred twenty-five billion, three hundred fourteen million, twenty-four thousand, one hundred forty-seven".