Base | Representation |
---|---|
bin | 10111010010110110101011… |
… | …00001111101000111000001 |
3 | 20201101002121120201210221011 |
4 | 23221123111201331013001 |
5 | 23203234020234421121 |
6 | 300540335010400521 |
7 | 13534624143222106 |
oct | 1351332541750701 |
9 | 221332546653834 |
10 | 51225362420161 |
11 | 1535a6107098a6 |
12 | 58b399a290141 |
13 | 22776b9658697 |
14 | c9146c29aaad |
15 | 5dc75125b7e1 |
hex | 2e96d587d1c1 |
51225362420161 has 4 divisors (see below), whose sum is σ = 51225835178800. Its totient is φ = 51224889661524.
The previous prime is 51225362420117. The next prime is 51225362420173. The reversal of 51225362420161 is 16102426352215.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 51225362420161 - 27 = 51225362420033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (51225362420101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 236216751 + ... + 236433508.
It is an arithmetic number, because the mean of its divisors is an integer number (12806458794700).
Almost surely, 251225362420161 is an apocalyptic number.
It is an amenable number.
51225362420161 is a deficient number, since it is larger than the sum of its proper divisors (472758639).
51225362420161 is a wasteful number, since it uses less digits than its factorization.
51225362420161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 472758638.
The product of its (nonzero) digits is 172800, while the sum is 40.
Adding to 51225362420161 its reverse (16102426352215), we get a palindrome (67327788772376).
The spelling of 51225362420161 in words is "fifty-one trillion, two hundred twenty-five billion, three hundred sixty-two million, four hundred twenty thousand, one hundred sixty-one".
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